SOLUTION: Pam jogged up a hill at 6 km/h and then jogged back down at 10 km/h. How many kilometers did she travel in all if her total jogging time was 1 hour and 20 minutes?

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Pam jogged up a hill at 6 km/h and then jogged back down at 10 km/h. How many kilometers did she travel in all if her total jogging time was 1 hour and 20 minutes?      Log On

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Question 30092: Pam jogged up a hill at 6 km/h and then jogged back down at 10 km/h. How many kilometers did she travel in all if her total jogging time was 1 hour and 20 minutes?
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
Let the distance be x.
1hour and 20 minutes = 1 1/3.--->4/3
Equation:

Common multiple is 30
30%28x%2F6%29%2B30%28x%2F10%29=30%284%2F3%29
5(x)+3(x)=10(4)
5x+3x=40
8x=40
x=5

Hence, she traveled 5km.
Paul.