SOLUTION: Kevin invested part of his 10,000 bonus in a certificate of deposit that paid 6% annual simple interest, and the remainder in a mutual fund that paid 11% annual simple interest. I

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Question 283771: Kevin invested part of his 10,000 bonus in a certificate of deposit that paid 6% annual simple interest, and the remainder in a mutual fund that paid 11% annual simple interest. If his total interest for that year was $900, how much did kevin invest in the mutual fund?
Found 4 solutions by mananth, ikleyn, greenestamps, josgarithmetic:
Answer by mananth(16949) About Me  (Show Source):
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Kevin invested part of his 10,000 bonus in a certificate of deposit that paid 6% annual simple interest, and the remainder in a mutual fund that paid 11% annual simple interest. If his total interest for that year was $900, how much did kevin invest in the mutual fund?
Let Kevin invest Rs x at 6%
He will invest 10000-x at 11%
6/100 * x +11/100 * = 900
0.06 x +0.11x=900
0.17x =900
x= 900/0.17
x=5294.11 which is the amount invested at 6%
10000-5294.11=4705.89 at 11 %


x=

Answer by ikleyn(53876) About Me  (Show Source):
You can put this solution on YOUR website!
.
Kevin invested part of his 10,000 bonus in a certificate of deposit that paid 6% annual simple interest,
and the remainder in a mutual fund that paid 11% annual simple interest.
If his total interest for that year was $900, how much did Kevin invest in the mutual fund?
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        The solution in the post by @mananth is incorrect, leading to wrong answer.
        I came to bring a correct solution.


Let x be the amount invested at 11%.
Then the amount invested at 6% is (10000-x).


Write the annual interest equation

    0.11x + 0.06*(10000-x) = 900.


Simplify and find x

    0.11x + 600 - 0.06x = 900,

    0.11x - 0.06x = 900 - 600,

          0.05x   =     300

              x   =     300/0.05 = 6000.



ANSWER.  Kevin invested  $6000 in the mutual fund.


CHECK.  The total annual interest was  0.11*6000 + 0.06*(10000-6000) = 900 dollars,

        which is precisely correct.

Solved correctly.



Answer by greenestamps(13355) About Me  (Show Source):
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$900 interest on an investment of $10,000 is a rate of return of 9%.

9% is three-fifths of the way from 6% to 11%; that means 3/5 of the total was invested at the higher rate. (If it helps, look at the three percentages 6, 9, and 11 on a number line.)

3/5 of $10,000 is $6000.

ANSWER: He invested $6000 in the mutual fund (and $4000 in the CD)


Answer by josgarithmetic(39823) About Me  (Show Source):
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10000 dollars invested at 6% and 11%, one year.
Total interest was 900 dollars the year.
How much invested at 11%?

P=10000
L=0.06
H=0.11
R=900
y= variable, how much at 11%
P-y = how much at 6%

Accounting for the one year earned interest
highlight_green%28L%28P-y%29%2BHy=R%29

LP-Ly%2BHy=R
%28H-L%29y%2BLP=R
%28H-L%29y=R-LP
highlight%28y=%28R-LP%29%2F%28H-L%29%29

Substituting the values
y=%28900-%280.06%29%2810000%29%29%2F%280.11-0.06%29
y=300%2F0.05
highlight%28y=6000%29