If an investment of $8000 increases by 15 percent at the end of each year, what is the fewest number of years until it doubles in value?
If it increases by 15% it becomes 115% of what it was before. To take 115% of
something is to multiply it by 1.15. So we want to know how many times
we must multiply $8000 by 1.15 until it just becomes $16000, or first exceeds
it. Let that number be n. Then to get the approximate nu,ber of years
Take the log of both sides:
Divide both sides by
or in 4 years it would be under $16000 and in 5 years
it would be over $16000.
Edwin