Question 217638: Please help...
One number is 8 less than another number. The sum of four times the larger and twice the smaller is 20. Find the larger number.
I got the second equation as 4n+8(2)=20 with n=1 but I don't know how to use that to find the answer.
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! Let n = one number,,,,,,,other number = (n-8)
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4(n) +2(n-8) = 20
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4n +2n -16 = 20
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6n = 36
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n=6,,,,,,(n-8) = -2,,,,,,numbers
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check,,,4 (6) + 2(-2) = 20,,,,,ok
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