SOLUTION: A person invested $16,000, part of 8% and the remainder at 6%. If the total yearly intrest from these investments was $1180, find the amount invested at each rate.

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Question 190266: A person invested $16,000, part of 8% and the remainder at 6%. If the total yearly intrest from these investments was $1180, find the amount invested at each rate.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = the amount invested @ 8%
16000+-+x will be the amount invested @ 6%
given:
.08x+%2B+.06%2A%2816000+-+x%29+=+1180
----------------------------------
.08x+%2B+960+-+.06x+=+1180
+.02x+=+220
x+=+11000
16000+-+x+=+16000+-+11000
16000+-+11000+=+5000
$11000 was invested @ 8% and $5000 was invested @ 6%
check:
.08x+%2B+.06%2A%2816000+-+x%29+=+1180
.08%2A11000+%2B+.06%2A5000+=+1180
.08%2A11000+%2B+.06%2A5000+=+1180
880+%2B+300+=+1180
1180+=+1180
OK