SOLUTION: Someone invests some money at 7% and 39000 more than 3 times the amount at 7%. The total interest earned is 39050. How much was invested at each amount? Thanks for any help.

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Question 188416: Someone invests some money at 7% and 39000 more than 3 times the amount at 7%. The total interest earned is 39050. How much was invested at each amount? Thanks for any help.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let x= the first amount invested @ 7%
given:
.07x+%2B+.07%2A%283x+%2B+39000%29+=+39050
.07x+%2B+.21x+%2B+2730+=+39050
.28x+=+36320
x+=+129714
3x+%2B+39000+=+3%2A129714+%2B+39000
3%2A129714+%2B+39000+=+428143
The amounts invested were:
$129,714 and $428,143