SOLUTION: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $

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Question 180064: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let n= number of nickels
Let d= number of dimes
given:
(1) 5n+%2B+10d+=+565
5%2A%28n+%2B+8%29+%2B+10%2A%282d%29+=+1045
5n+%2B+40+%2B+20d+=+1045
(2) 5n+%2B+20d+=+1005
Subtract (1) from (2)
(2) 5n+%2B+20d+=+1005
(1) -5n+-+10d+=+-565
10d+=+440
d+=+44
He has 44 dimes
check:
(1) 5n+%2B+10d+=+565
5n+%2B+10%2A44+=+565
5n+=+565+-+440
5n+=+125
n+=+25
5n+%2B+40+%2B+20d+=+1045
(2) 5n+%2B+20d+=+1005
5%2A25+%2B+20%2A44+=+1005
125+%2B+880+=+1005
1005+=+1005
OK