SOLUTION: Tickets to a local movie were sold for $6.00 for adults and $4.50 for students. If 276 tickets were sold for a total of $1632.00, how many student tickets were sold?
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Question 1208613: Tickets to a local movie were sold for $6.00 for adults and $4.50 for students. If 276 tickets were sold for a total of $1632.00, how many student tickets were sold? Found 3 solutions by math_tutor2020, josgarithmetic, greenestamps:Answer by math_tutor2020(3816) (Show Source):
x+y = 276 since there are 276 total people
Solving for x gives us x = -y+276
6x = money from just the adults
4.5y = money from just the students
6x+4.5y = total amount of money brought in
6x+4.5y = 1632
6( x )+4.5y = 1632
6( -y+276 )+4.5y = 1632 ....... replace x with -y+276
I'll let the student take over from here.
The given information gives us these two equations:
the total number of tickets sold was 276
the total cost of the tickets, at $6 each for adults and $4.50 each for students, was $1632
In both of the responses you have received from other tutors, the solution of the problem is set up using substitution -- solving the first equation for either x or y and substituting in the second.
When both equations are given in this "ax+by=c" form, I think a solution using elimination is easier.
Multiply the first equation by 6 so that both equations contain the term "6x":
Now subtract the second equation from the first, eliminating variable x, and solve the resulting equation for y:
The number of student tickets sold was y = 16.
ANSWER: 16
CHECK:
The number of student tickets was 16, so the number of adult tickets was 276-16 = 260.
260(6)+16(4.5)=1560+72=1632