|
Question 1207881: Commonwealth Edison Company supplies electricity to residential customers for a monthly customer charge of $10.55 plus 9.44 cents per kilowatt-hour for up to 600 kilowatt-hours.
(a) Write a linear equation that relates the monthly charge C,in dollars, to the number x of kilowatt-hours used in a month, 0 <= x <= 600.
My equation is C(x) = 9.44x + 10.55, where x = the number of kilowatt-hours. However, the book's equation is C(x) = 0.0944x + 10.55.
Tell me, where did 0.0944 come from in the book's equation?
(b) Graph this equation.
I don't know how to upload pictures on this website.
(c) What is the monthly charge for using 200 kilowatt-hours?
For (c), I must let x = 200 in the equation. Yes?
(d) What is the monthly cost for using 500 kilowatt-hours?
For (d), I must let x = 500 in the equation. Yes?
(e) What is the monthly charge for using 700 kilowatt-hours?
I see that 700 falls outside the given range [0, 600].
So, it cannot be determined. Yes?
(f) Interpret the slope of the line.
Let x = number of kilowatt-hours
So, each x used adds $0.0944 to the bill.
You say?
Answer by ikleyn(52781)   (Show Source):
You can put this solution on YOUR website! .
Your equation C(x) = 9.44x + 10.55 dollars is  .
The correct equation is
C(x) = 0.0944x + 10.55 dollars.
The coefficient 0.0944 is the rate 9.44 cents per kilowatt-hour  to dollars per kilowatt-hour.
Conversion is needed to have all the terms (all the numbers) of the equation in consistent units.
So, all your following calculations must be redone.
Solved, answered and explained, in full.
///////////////////
Similar problem (a TWIN) was solved at this forum couple of days ago under the link
https://www.algebra.com/algebra/homework/Graphs/Graphs.faq.question.1207854.html
with complete explanations.
|
|
|
| |
