SOLUTION: Sara deposited $1400 for 1 year at 10%, compound semiannually. b. What percent interest was added each time? c. What was the balance in Sara's account at the end of 1 year?

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Sara deposited $1400 for 1 year at 10%, compound semiannually. b. What percent interest was added each time? c. What was the balance in Sara's account at the end of 1 year?       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1201119: Sara deposited $1400 for 1 year at 10%, compound semiannually.
b. What percent interest was added each time?
c. What was the balance in Sara's account at the end of 1 year?

Found 3 solutions by Theo, mananth, ikleyn:
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
10% per year compounded semi-annually / 2 = 5% per half year.
she deposited 1400.
at the end of the first semi-annual period, she earned 5%.
the remaining bslance in the account was 1400 * 1.05 = 1470.
at the end of the second semi-annuial period, she erned 5%.
the remaining bgalance in the account was 1470 * 1.05 = 1543.5.
that's how much she had in the account at the end of 1 year.

Answer by mananth(16949) About Me  (Show Source):
You can put this solution on YOUR website!
t the end of one year A = $1,543.50

Answer by ikleyn(53618) About Me  (Show Source):
You can put this solution on YOUR website!
.Sara deposited $1400 for 1 year at 10%, compound semiannually.
b. What percent interest was added each time?
c. What was the balance in Sara's account at the end of 1 year?
~~~~~~~~~~~~~~~~~~~~~~~~~


(b)  What percent interest was added each time?


     Two semi-annual compounding produce the effective increase per year

          1%2B0.1%2F2%29%5E2 = 1%2B0.05%29%5E2 = 1.05%5E2 = 1.1025,

     so the effective interest per year is  10.25%.



(c)  What was the balance in Sara's account at the end of 1 year?


     The balance in Sara's account at the end of 1 year is

         1400%2A%281+%2B+0.1%2F2%29%5E2 = 1400%2A1.05%5E2 = 1543.50 dollars.

Solved. Both questions are answered.