SOLUTION: Frank invests $3500 dollars into an account earning interest compounded quarterly. After 10 years there is $5050 in the account. What was the interest rate?
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Question 1198963: Frank invests $3500 dollars into an account earning interest compounded quarterly. After 10 years there is $5050 in the account. What was the interest rate? Found 3 solutions by MathLover1, josgarithmetic, math_tutor2020:Answer by MathLover1(20849) (Show Source):
Variables:
A = final account value after t years
P = deposit or starting value
r = annual interest rate in decimal form
n = compounding frequency
t = number of years
In this case:
A = 5050
P = 3500
r = unknown
n = 4
t = 10
Let's solve for the variable r.
A = P*(1+r/n)^(n*t)
5050 = 3500*(1+r/4)^(4*10)
5050/3500 = (1+r/4)^(40)
1.442857143 = (1+r/4)^(40)
(1+r/4)^(40) = 1.442857143
1+r/4 = (1.442857143)^(1/40)
1+r/4 = 1.009207765
r/4 = 1.009207765 - 1
r/4 = 0.009207765
r = 4*0.009207765
r = 0.03683106
r = 0.0368
r*(100%) = 0.0368*100% = 3.68%
In other words, we move the decimal point two spots to the right to go from 0.0368 to 3.68%
To verify the answer, we can use a TVM calculator such as this https://www.geogebra.org/m/mvv2nus2
A similar feature is found on any TI83 or TI84 calculator.
TVM = time value of money
The input values are
N = 10
I% = left blank
PV = -3500
PMT = 0
FV = 5050
P/Y = 1
C/Y = 4
N represents the number of periods. In this case it's the number of years.
PV is negative to represent a cash outflow.
PMT represents the periodic payment. We type zero here to indicate we don't have periodic payments; rather we have a one-time deposit instead.
C/Y stands for "compoundings per year"
After you input those items into the proper boxes, press the "solve for I%" button to have 3.68 show up in that box.