SOLUTION: A carpenter purchased 70 ft of redwood and 80 ft of pine for a total cost of $335. A second purchase, at the same prices, included 100 ft of redwood and 50 ft of pine for a total c

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Question 1169905: A carpenter purchased 70 ft of redwood and 80 ft of pine for a total cost of $335. A second purchase, at the same prices, included 100 ft of redwood and 50 ft of pine for a total cost of $395. Find the cost per foot of redwood and of pine.
Found 3 solutions by ikleyn, MathTherapy, greenestamps:
Answer by ikleyn(52814) About Me  (Show Source):
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Let x = price per 1 ft of redwood;  y = price for 1 ft of pine.


Then you have the system of these 2 equations in 2 unknowns


    70x + 80y = 335    (1)

   100x + 50y = 395    (2)


Appliy any method you want (you know, you like). I will use the determinant method (= same as the Cramer's rule)


    x = %28335%2A50+-+395%2A80%29%2F%2870%2A50-100%2A80%29 = 3.30 dollars per foot

    y = %2870%2A395-100%2A335%29%2F%2870%2A50-100%2A80%29 = 1.30 dollars per foot.

Solved.


Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

A carpenter purchased 70 ft of redwood and 80 ft of pine for a total cost of $335. A second purchase, at the same prices, included 100 ft of redwood and 50 ft of pine for a total cost of $395. Find the cost per foot of redwood and of pine.
Let cost of each foot of redwood and pine, be R and P, respectively
We then get: 70R + 80P = 335______14R + 16P = 67 ------- eq (i)
100R + 50P = 395_____20R + 10P = 79 ------- eq (ii)
6R - 6P = 12 ------ Subtracting eq (i) from eq (ii)
6(R - P) = 6(2)______R - P = 2________R = 2 + P ------- eq (iii)
14(2 + P) + 16P = 67 ------- Substituting 2 + P for R in eq (i)
28 + 14P + 16P = 67
30P = 39
Cost of each foot of pine, or
R = 2 + 1.30 ------- Substituting 1.30 for P in eq (iii)
Cost of each foot of redwood: highlight_green%28%22%243.30%22%29

Answer by greenestamps(13203) About Me  (Show Source):
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The given information gives us two equations:

70x%2B80y+=+335
100x%2B50y+=+395

My definite preference for solving a system of equations in this form is elimination. Multiply one or both equations by constants so that the coefficients of one of the variables are the same in the two equations; then subtract one equation from the other to eliminate that variable.

350x%2B400y+=+1675
800x%2B400y+=+3160
450x+=+1485
x+=+1485%2F450+=+3.3

Then substitute x=3.3 in either original equation to solve for y.

70%283.3%29%2B80y+=+335
231%2B80y+=+335
80y+=+104
y+=+1.3

ANSWERS: x = $3.30 per foot for redwood; y = $1.30 per foot for pine.