|
Question 1169905: A carpenter purchased 70 ft of redwood and 80 ft of pine for a total cost of $335. A second purchase, at the same prices, included 100 ft of redwood and 50 ft of pine for a total cost of $395. Find the cost per foot of redwood and of pine.
Found 3 solutions by ikleyn, MathTherapy, greenestamps: Answer by ikleyn(52814) (Show Source):
You can put this solution on YOUR website! .
Let x = price per 1 ft of redwood; y = price for 1 ft of pine.
Then you have the system of these 2 equations in 2 unknowns
70x + 80y = 335 (1)
100x + 50y = 395 (2)
Appliy any method you want (you know, you like). I will use the determinant method (= same as the Cramer's rule)
x = = 3.30 dollars per foot
y = = 1.30 dollars per foot.
Solved.
Answer by MathTherapy(10555) (Show Source):
You can put this solution on YOUR website!
A carpenter purchased 70 ft of redwood and 80 ft of pine for a total cost of $335. A second purchase, at the same prices, included 100 ft of redwood and 50 ft of pine for a total cost of $395. Find the cost per foot of redwood and of pine.
Let cost of each foot of redwood and pine, be R and P, respectively
We then get: 70R + 80P = 335______14R + 16P = 67 ------- eq (i)
100R + 50P = 395_____20R + 10P = 79 ------- eq (ii)
6R - 6P = 12 ------ Subtracting eq (i) from eq (ii)
6(R - P) = 6(2)______R - P = 2________R = 2 + P ------- eq (iii)
14(2 + P) + 16P = 67 ------- Substituting 2 + P for R in eq (i)
28 + 14P + 16P = 67
30P = 39
Cost of each foot of pine, or 
R = 2 + 1.30 ------- Substituting 1.30 for P in eq (iii)
Cost of each foot of redwood:
Answer by greenestamps(13203) (Show Source):
|
|
|
| |