SOLUTION: 3 notebooks and 2 pens cost P330. 2 notebooks and 3 pens cost P240. find the cost of 1 notebook and 1 pen.

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: 3 notebooks and 2 pens cost P330. 2 notebooks and 3 pens cost P240. find the cost of 1 notebook and 1 pen.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1166617: 3 notebooks and 2 pens cost P330. 2 notebooks and 3 pens cost P240. find the cost of 1 notebook and 1 pen.
Found 3 solutions by josgarithmetic, greenestamps, ikleyn:
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
You have seen a solution for something like this already.

Answer by greenestamps(13195) About Me  (Show Source):
You can put this solution on YOUR website!


The given information tells us

3n%2B2p=330
2n%2B3p=240

There are endless variations on how to solve this pair of equations.

However, note that you are not asked to find the cost of each notebook and each pen -- you are only asked to find the cost of one notebook and one pen.

The given information makes it very easy to do that.

Add the two equations to find that 5 notebooks and 5 pens cost P570; that means one of each costs P570/5 = P114.

ANSWER: The cost of one notebook and one pen is P114.


Answer by ikleyn(52747) About Me  (Show Source):
You can put this solution on YOUR website!
.

I will interpret your question in THIS way:

    Find the cost of 1 notebook and 1 pen together as one purchase (= not separately).


Solution

From the condition, you have these two equations

    3N + 2P = 330   (1)

    2N + 3P = 240   (2)


Add the equations

    5N + 5P = 330 + 240 = 570.


Divide both sides by 5

     N +  P = 570/5 = 114.


ANSWER.  1 notebook and 1 pen cost together  P114.

Solved.


-----------

By the way, English (as any other language) has enough words to formulate any thought (and any Math problem, in particular)

in precise and accurate manner.


In Math, a standard and usual REQUIREMENT by DEFAULT is to formulate the problem in a way when interpretation/interpretations
are not needed and are not necessary.

When interpretation/interpretations IS / (ARE) REQUIRED, it is just DEFECTIVE Math problem.


Please keep it in your mind.