Question 1163731: An executive invests $21,000, some at 8% and the rest at 6% Annual interest. if he receive an annual return of &1,620, how much is invested at each rate
At 8% interest =
At 6% interest =
Found 3 solutions by MathLover1, MathTherapy, greenestamps: Answer by MathLover1(20849) (Show Source): Answer by MathTherapy(10552) (Show Source):
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An executive invests $21,000, some at 8% and the rest at 6% Annual interest. if he receive an annual return of &1,620, how much is invested at each rate
At 8% interest =
At 6% interest =
Let amount invested at 8% be E
Then amount invested at 6% = 21,000 - E
We then get: .08E + .06(21,000 - E) = 1,620
.08E + 1,260 - .06E = 1,620
.08E - .06E = 1,620 - 1,260
.02E = 360
Amount invested in the 8%-fund, or 
You should now be able to find the amount invested in the 6% fund.
Answer by greenestamps(13200) (Show Source):
You can put this solution on YOUR website!
If a formal algebraic solution is not required, here is a quick and easy solution method.
(1) All $21,000 at 6% would yield $1260 interest; all at 8% would yield $1680 interest.
(2) The actual interest, $1620, is 6/7 of the way from $1260 to $1680. (Picture the three numbers on a number line -- 1260, 1620, and 1680. 1260 to 1680 is 420; 1260 to 1620 is 360; 360/420 = 6/7.)
(3) That means 6/7 of the total was invested at the higher rate.
ANSWER: 6/7 of the $21,000, or $18,000, was invested at 8%; the other $3000 was invested at 6%.
CHECK: .06(3000)+.08(18000) = 180+1440 = 1620
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