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Question 1159199: A man invested Php 6,000, part of it at 3% and the rest at 4%. The total annual income from the
two investments is Php 208. How much is invested at each of these rates?
Answer by ikleyn(52803)   (Show Source):
You can put this solution on YOUR website! .
0.04*x + 0.03*(6000-x) = 208
From the equation,
x =  = 2900.
ANSWER. Php 2800 was invested at 4%, and the rest, 6000-2800 = 3200 Php was invested at 3%.
CHECK. 0.04*2800 + 0.03*3200 = 208 Php. ! Correct !
Solved.
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It is a standard and typical problem on investments.
If you need more details, or if you want to see other similar problems solved by different methods, look into the lesson
- Using systems of equations to solve problems on investment
in this site.
You will find there different approaches (using one equation or a system of two equations in two unknowns), as well as
different methods of solution to the equations (Substitution, Elimination).
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Systems of two linear equations in two unknowns".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.
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