SOLUTION: Money is invested at two rates of interest. One rate is 6% and the other is 2%.If there is $1200 more invested at 6% than at 2%, find the amount invested at each rate if the tot

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Money is invested at two rates of interest. One rate is 6% and the other is 2%.If there is $1200 more invested at 6% than at 2%, find the amount invested at each rate if the tot      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1158346: Money is invested at two rates of interest. One rate is 6% and the other is
2%.If there is $1200 more invested at 6% than at 2%, find the amount invested at each rate if the total annual interest received is $890.Let x=amount invested at
6% and y= amount invested at 2%.Then the system that models the problem is
{x=y+1200
0.06x+0.02y=890.Solve the system by using the method of addition.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(1) +x+-+y+=+1200+
(2) +.06x+%2B+.02y+=+890+
--------------------------------
(2) +6x+%2B+2y+=+89000+
(2) +3x+%2B+y+=+44500+
------------------------------
Add (1) and (2)
(1) +x+-+y+=+1200+
(2) +3x+%2B+y+=+44500+
------------------------------
+4x+=+45700+
+x+=+11425+
and
(1) +x+-+y+=+1200+
(1) +11425+-+y+=+1200+
(1) +y+=+10225+