Question 1157329: A. Class of 2018 graduates were 1250 students, 40% of them were female students, and the rest were male, 10% of the female students got a grade of “A” and 10 students of the female graded “A” were international students. Class of 2019 had 875 male students, also 10 female students got an “A” in their grade in class 2019, where the total number of students did not change from last year.
Calculate the following: (Show your calculations-write the steps) (15 marks, 3 marks each)
1. The number of female students.
2. The number of Female students with a grade “A”.
3. The percentage of the female international students graded “A” out of the total number of female students with a grade “A”.
4. What is the percentage increase or decrease in the number of male students in comparison to class 2018?
5. What is the percentage of female students who got “A” out of the female students?
B. 23, 30, 1, 49, 2, 36, 7, 23, 13, 9, 30, 17, 20.
Calculate the mean median and mode. (10 marks)
Answer by KMST(5434)   (Show Source):
You can put this solution on YOUR website! Question A:
1. The number of female students.
  of  is  or  .
If you type in a calculator     ,
the display will probably show "1250 x 0.4" and pressing  will give you the result.
2. The number of female students with a grade “A”.
If 10% of those  female students got a grade of "A",
the number of female students with a grade “A” can be calculated multiplying that number times  , or dividing by 10, or moving the decimal point one place to the left.
Either way, the answer is  female students with a grade “A”.
3. The percentage of the female international students graded “A” out of the total number of female students with a grade “A”.
If out of those  10 students of the female students graded “A”,
10 of them were international students, they are a  fraction of the number of students female students graded “A”,
As a percentage that fraction is 
4. What is the percentage increase or decrease in the number of male students in comparison to class 2018?
The number of male students in the class of 2018 must be  ,
because the total number of students was and we found that  of those were female students.
The number of male students in class of 2019, being  is more than  ,
and represents an  of  .
As a fraction of the number of male students in class of 2018,
that increase is  .
That ratio does not translate to an exact decimal or percentage,
so we have to round it to  , or  , or  .
5. What is the percentage of female students who got “A” out of the female students?
The question tells us at the very start that "10% of the female students got a grade of A", so no calculation would be needed.
We could calculate it back from the number of female students found in part 1, and the number of female students with a grade “A” calculated in part 2 as 10% of the result of part 1,
as the ratio  .
Maybe the question for part 5 was supposed to be different
Question B. 23, 30, 1, 49, 2, 36, 7, 23, 13, 9, 30, 17, 20.
Calculate the mean median and mode.
The mean is the average, found adding all values and dividing by the number of values added.
there are 13 values listed, so
The median is the value in the middle, a value such that there as many values greater or equal than the median as values lesser or equal than the median.
To find, just listing the values in order from least to greatest. If there is an odd number of values, you just pick the one in the middle of the list.
In this case, the median happens to be equal to the mean, but that is not always the case.
 would be the seventh value in such a list.
It is greater than 6 of the listed values: 1, 2, 7, 9, 13, and 17.
It is lesser than the other 6 numbers in the list: 23, 23, 30, 30, 36, and 49.
The mode is the most frequent value, and there could be more than one.
In this case there are to modes:  and  . Each one appears twice in that list.
we could say that the distribution of values is "bimodal".
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