Question 1144256: Investments: Aaron invested equal amounts of money at 5%, 7%, 9%, and 11% annual interest. If the four investments yielded a total of $1440 annual interest, find the total amount invested.
Found 3 solutions by ankor@dixie-net.com, ikleyn, greenestamps:
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Investments: Aaron invested equal amounts of money at 5%, 7%, 9%, and 11% annual interest.
If the four investments yielded a total of $1440 annual interest, find the total amount invested.
Let a = total amt invested
.05a +.07a + .09a + .11a = 1440
.32a = 1440
a = 1440/.32
a = $4500 invested
then
.05(4500) = 225 invested at 5%
.07{4500) = 315 " " 7%
.09(4500) = 405 " " 9%
.11(4500) = 495 " " 11%
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total inv: 1400
Answer by ikleyn(52775)  (Show Source):
You can put this solution on YOUR website! .
Let "x" be the COMMON EQUAL value of each of the four investments.
Then the condition says that
0.05x + 0.07x + 0.09x + 0.11x = 1440 dollars (total annual interest).
Simplify and solve this equation
0.32x = 1440
x =  = 4500 dollars.
The total amount invested is 4x = 4*4500 = 18000 dollars.
Ignore the solution and the answer of the other tutor, since they are W R O N G.
Answer by greenestamps(13198)  (Show Source):
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