SOLUTION: Part of the proceeds from a garage sale was $265 worth of $5 and $20 bills. If there were 3 more $5 bills than $20 bills. Find the number of each denomination There were ? $5 bi

Put aside that three extra $5 bills.


Then you have an updated collection of equal number of $5 and $20 dollars bills, and this collection is worth  265 - 15 = 250 dollars.


Now you can group $5 and $20 dollar bills in sets containing one $5-dollar bill and one $20-dollar bill.


Each set is worth $25, and the number of sets is   = 10.


So, the original collection contains  10  of $20-dollar bills and  10+3 = 13 of $5-dollar bills.     ANSWER