SOLUTION: Say that a business determines its profit function is: P ( x ) = x^2 - 6 x + 1 where X is the number of units produced in thousands and P ( x ) is the profit made in thousands of
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Question 1127391: Say that a business determines its profit function is: P ( x ) = x^2 - 6 x + 1 where X is the number of units produced in thousands and P ( x ) is the profit made in thousands of dollars.
Does this mean that the business should produce 3,000 units to maximize its profit Found 3 solutions by josmiceli, stanbon, ikleyn:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Yes, but the equation should be:
in order for the peak to be a maximum
and for to be positive when
is a maximum
You can put this solution on YOUR website! Say that a business determines its profit function is: P ( x ) = x^2 - 6 x + 1 where X is the number of units produced in thousands and P ( x ) is the profit made in thousands of dollars.
Does this mean that the business should produce 3,000 units to maximize its profit
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Max profit occurs when x = -b/(2a) = 6/2 = 3
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Answer: Yes
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Cheers,
Stan H.
Say that a business determines its profit function is: P ( x ) = x^2 - 6 x + 1 where X is the number of units
produced in thousands and P ( x ) is the profit made in thousands of dollars.
Does this mean that the business should produce 3,000 units to maximize its profit
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Let me make couple of notices:
1. The given quadratic function has a MINIMUM at x= 3 thousands.
2. The given quadratic function HAS NO a MAXIMUM at x= 3 thousands.
Therefore, the question is IRRELEVANT to the given part.
Not only irrelevant - it CONTRADICTS to the given part.
Have a nice evening / night / morning / day .
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