SOLUTION: Bennett purchased some beef and some chicken for a family barbecue. The beef cost $5.70 per pound and the chicken cost $3.20 per pound. He brought a total of 11 lb of meat and spen

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Bennett purchased some beef and some chicken for a family barbecue. The beef cost $5.70 per pound and the chicken cost $3.20 per pound. He brought a total of 11 lb of meat and spen      Log On

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Question 1126633: Bennett purchased some beef and some chicken for a family barbecue. The beef cost $5.70 per pound and the chicken cost $3.20 per pound. He brought a total of 11 lb of meat and spent $47.70. How much of each type of meat did he purchase?
Answer by ikleyn(52776) About Me  (Show Source):
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Bennett purchased some beef and some chicken for a family barbecue. The beef cost $5.70 per pound and the chicken cost $3.20 per pound.
He highlight%28cross%28brought%29%29 bought a total of 11 lb of meat and spent $47.70. How much of each type of meat did he purchase?
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    B +     C = 11    lb        (1)   ("He bought a total of 11 lb of meat")
5.7*B + 3.2*C = 47.7  dollars   (2)   ("He pent $47.70")


From eq(1), express  B = 11-C  and substitute it into equation (2).


5.7*(11-C) + 3.2*C = 47.7.


Solve this equation for C.


Then evaluate  B = 11-C.

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I used the Substitution method to solve the system of equations.

So, on the way you learned on how the substitution method works.