SOLUTION: A broker brought stocks in two companies for a total investment of $44,000. When he sold them, he gained 12% on the first company and lost 10% on the second company for a total pro

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: A broker brought stocks in two companies for a total investment of $44,000. When he sold them, he gained 12% on the first company and lost 10% on the second company for a total pro      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1120235: A broker brought stocks in two companies for a total investment of $44,000. When he sold them, he gained 12% on the first company and lost 10% on the second company for a total profit of $2200. How much did he invest in each company?

Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let x = How much did he invest at +12%.


Then your equation is


0.12x - 0.1*(44000-x) = 2200    dollars.


Simplify and solve for x.


Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x invested in first company
y invested in second company

system%28x%2By=44000%2C0.12x-0.1y=2200%29

system%28x%2By=44000%2C6x-5y=110000%29

system%285x%2B5y=220000%2C6x-5=110000%29

highlight%28x=30000%29
-
highlight%28y=14000%29