SOLUTION: e
A chemical company makes two brands of antifreeze. The first brand is
65
%
pure antifreeze, and the second brand is
90
%
pure antifreeze. In order to obtain
90
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A chemical company makes two brands of antifreeze. The first brand is
65
%
pure antifreeze, and the second brand is
90
%
pure antifreeze. In order to obtain
90
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A chemical company makes two brands of antifreeze. The first brand is
65
%
pure antifreeze, and the second brand is
90
%
pure antifreeze. In order to obtain
90
gallons of a mixture that contains
75
%
pure antifreeze, how many gallons of each brand of antifreeze must be used? Answer by ikleyn(52776) (Show Source):
Let "x" the amount of the 65% antifreeze to be mixed, in gallons.
Then the amount of the 90% antifreeze is (90-x) gallons.
Your equation is
= 0.75.
The numerator of this formula is the amount of the pure antifreeze in the mixture,
that came from each of the two input solutions.
Divided by the total volume of 90 gallons, it is the concentration of the antifreeze in the mixture,
which must be 0.75 = 75%, according to the problem requirement.
To solve the equation, multiply both sides by 90. You will get
0.65x + 0.9*90 - 0.9x = 0.75*90
-0.25x = 0.75*90 - 0.9*90 = -13.5 ====> x = = 54.
Answer. 54 gallons of the 65% and (90-54) = 36 gallons of the 90% antifreeze should be mixed to get 90 gallons of the 75% antifreeze.
Check. = 0.75 = 75% ! Correct !
You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization, from very detailed to very short.
Read them and become an expert in solution mixture word problems.
