Question 1110629: $2500 is invested at 6% per year compounded annually. How long will it take this investment to grow to $10,000? Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! 2500(1+0.06)^t = 10000
1.06^t = 4
tlog(1.06) = log(4)
t = log(4)/log(1.06)
t = 23.8 years
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Check:
2500(1+.06)^23.8 = 2500(1.06)^23.8 = 2500*4 = 10000 Correct