SOLUTION: a woman has a total of 9,000 to invest.she invest part of the money in an account that pays 8% per year and the rest in an account that pays 9%per year if the interest earned in th

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Question 1109966: a woman has a total of 9,000 to invest.she invest part of the money in an account that pays 8% per year and the rest in an account that pays 9%per year if the interest earned in the first year is 750 how much did she invest in each account
Answer by ikleyn(52775) About Me  (Show Source):
You can put this solution on YOUR website!
.
interest + interest      = total interest


0.08*x   + 0.09*(9000-x) = 750    dollars


0.08x + 810 - 0.09x = 750

-0.01x = 750 - 810 = -60  ====>  x = %28-60%29%2F%28-0.01%29 = 6000.


Answer.  $6000 was invested at 8%.  The rest   9000-6000 = 3000 dollars were invested at 9%.


Check.   0.08*6000 + 0.09*3000 = 480 + 270 = 750 dollars.   ! Correct !

Solved.

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To see many other similar solved problems on investment,  look into the lesson
    - Using systems of equations to solve problems on investment
in this site.

You will find there different approaches  (using one equation or a system of two equations in two unknowns),  as well as
different methods of solution to the equations  (Substitution,  Elimination).

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic "Systems of two linear equations in two unknowns".


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Free of charge online textbook in ALGEBRA-I
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to your archive and use it when it is needed.