SOLUTION: Marge invests $7,000 , part at 6% and part at 9%. If she ears $493 interest how much is invested in each account.

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Question 1102971: Marge invests $7,000 , part at 6% and part at 9%. If she ears $493 interest how much is invested in each account.

Found 2 solutions by ikleyn, addingup:
Answer by ikleyn(52925)   (Show Source):
You can put this solution on YOUR website!
.

0.06*x + 0.09*(7000-x) = 493. Solve for x. 6x + 9*(7000-x) = 49300 6x + 63000 - 9x = 49300 ====> -3x = 49300 - 63000 = -13700 ====> x = = 4566.67 dollars invested at 6%. The rest, 7000 - 4566.67 = 2433.33 dollars invested at 9%.

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Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website!
Of a total of 7000 she invests x money at 6%. And the rest, 7000 - x, she invests at 9%
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0.06x + 0.09(7000 - x) = 493
0.06x + 630 - 0.09x = 493
-0.03x = -137
x = 4566.67 this is the amount invested at 6x. The amount invested at 9% is 7000-4566.67 = 2433.33