SOLUTION: Martha, Jeremy and Susanne had $40, $50 and $60 respectively. Martha gave 2/5 of her money to Jeremy who then gave 1/3 of his money to Susanne, who then gave half of her final amou

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Martha, Jeremy and Susanne had $40, $50 and $60 respectively. Martha gave 2/5 of her money to Jeremy who then gave 1/3 of his money to Susanne, who then gave half of her final amou      Log On

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Question 1100363: Martha, Jeremy and Susanne had $40, $50 and $60 respectively. Martha gave 2/5 of her money to Jeremy who then gave 1/3 of his money to Susanne, who then gave half of her final amount to Martha. Place the children in the order of most to least amount of money.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = amount Martha has currently
Let +b+ = amount Jeremy has currently
Let +c+ = amount Susanne has currently
---------------------------------------
(1)
+a++=+40+
+b+=+50+
+c+=+60+
----------------
(2)
Martha gives 2/5 of her money to Jeremy
+a+=+40+-+%282%2F5%29%2A40+
+a+=+%283%2F5%29%2A40+
+a+=+24+
and
+b+=+50+%2B+%282%2F5%29%2A40+
+b+=+50+%2B+16+
+b+=+66+
+c+=+60+
--------------------------
(3)
Jeremy gives 1/3 of his money to Suzanne
+a+=+24+
+b+=+66+-+%281%2F3%29%2A66+
+b+=+%282%2F3%29%2A66+
+b+=+44+
and
+c+=+60+%2B+%281%2F3%29%2A66+
+c+=+60+%2B+22+
+c+=+82+
---------------------------
(4)
+a+=+24+%2B+%281%2F2%29%2A82+
+a+=+24+%2B+41+
+a+=+65+
and
+b+=+44+
+c+=+%281%2F2%29%2A82+
+c+=+41++
----------------------------
(5)
+a+=+65+
+b+=+44+
+c+=+41+
---------------
M. has 65
J has 44
S has 41