Question 1099048: An actor invests some money at 5%, and $22000 more than twice the amount at 11%. The total annual interest earned from the investment is $17540. How much did he invest at each amount? Use the six-step method.
Answer by jorel1380(3719)   (Show Source):
You can put this solution on YOUR website! Let n and 2n+22,000 be the amounts invested at 5% and 11%, respectively. Then:
.05n+.11(2n+22,000)=17540
.05n+.22n+2420=17540
.27n=15120
n=56000
$56,000 was invested at 5%, and $134,000 was invested at 11%
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