SOLUTION: James paid $3.40 for lunch using a total of 16 nickels and quarters. How many of each coin did he have?

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Question 1088586: James paid $3.40 for lunch using a total of 16 nickels and quarters. How many of each coin did he have?
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let Q be the number of quarters.

Then the number of nickels is (16-Q).


The quarters contribute 25Q      cents to the total.

The nickels  contribute 5*(16-Q) cents to the total.


The total value equation is

25Q + 5*(16-Q) = 340  cents,

25Q + 80 - 5Q = 340,

20Q = 340 - 80 = 260  ====>  Q = 260%2F20 = 13.


Answer.  13 quarters and 16-13 = 3 nickels.

Solved.

There is entire bunch of lessons on coin problems
    - Coin problems
    - More Coin problems
    - Solving coin problems without using equations
    - Kevin and Randy Muise have a jar containing coins
    - Typical coin problems from the archive
    - More complicated coin problems
    - Solving coin problems mentally by grouping without using equations
    - Santa Claus helps solving coin problem
    - OVERVIEW of lessons on coin word problems
in this site.

You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.

Read them and become an expert in solution of coin problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Coin problems".