SOLUTION: shawn has an annual interest income of $3290 from two investments. he has $7000 more invested at 8% than he has invested at 6%. find the amount invested in each rate ?
Algebra ->
Customizable Word Problem Solvers
-> Finance
-> SOLUTION: shawn has an annual interest income of $3290 from two investments. he has $7000 more invested at 8% than he has invested at 6%. find the amount invested in each rate ?
Log On
Question 108197: shawn has an annual interest income of $3290 from two investments. he has $7000 more invested at 8% than he has invested at 6%. find the amount invested in each rate ? Answer by elima(1433) (Show Source):
You can put this solution on YOUR website! shawn has an annual interest income of $3290 from two investments. he has $7000 more invested at 8% than he has invested at 6%. find the amount invested in each rate ?
=======================================
.08x+.06y=3290
y=x+7000
-------------------
.08x+.06(x+7000)=3290
.08x+.06x+420=3290
.14x=2870
x=20500
.08(20500)+.06y=3290
1640+.06y=3290
.06y=1650
y=27500
===================
At 8% interest = $20500
at 6%interest = $27500
:)