SOLUTION: A man buys a lamp and a table for 390 $. The table cost 80 $ more than the lamp. Find the cost of each aricle.

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Question 107455: A man buys a lamp and a table for 390 $. The table cost 80 $ more than the lamp. Find the cost of each aricle.
Found 3 solutions by Dan3322, Annabelle1, MathLover1:
Answer by Dan3322(1) About Me  (Show Source):
You can put this solution on YOUR website!
A man buys a lamp and a table for 390 $. The table cost 80 $ more than the lamp. Find the cost of each aricle.

Answer by Annabelle1(69) About Me  (Show Source):
You can put this solution on YOUR website!
let the cost of the lamp be x
the cost of the table is then x+80
the total cost is then x+x+80
=2x+80
this is equal to 390
2x+80=390
Solved by pluggable solver: SOLVE a linear equation
Solve 2%2Ax%2B80=390. Move 80 to the right: 2%2Ax=390-80. Divide by 2: x=%28390-80%29%2F2=310%2F2+=+155


so the lamp(x) was $155
the table then 155+80=235

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
given:
A man buys a lamp+=+L and a table+=+T for $390.
The T cost $80 more than the L.
Find the+cost of each aricle.
then:
L+%2B+T+=+390
since T+=+L%2B+80
we will substitute it
L%2B+%28L%2B+80%29+=+390
+2L+%2B+80+=+390
2L+=+390+-+80
2L+=+310
L+=+310%2F2
L+=+155............the cost of the lamp
then
T+=+155+%2B+80
T+=+235..............the cost of the table
check:
L+%2B+T=+390
155+%2B+235+=+390
390+=+390