SOLUTION: The profit of a retail store is y=2500+36x-0.2x^2 . Use the derivative if it would be profitable for the daily advertising budget to be increased if the daily advertising budget is
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Question 1056699: The profit of a retail store is y=2500+36x-0.2x^2 . Use the derivative if it would be profitable for the daily advertising budget to be increased if the daily advertising budget is
(a) $60
(b) $300
(c) what is the maximum value for x below which it is profitable to increase the advertising? Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! I'll do the answers backwards,
c)
An increase in profits occurs as long as the derivative is greater than zero.
b) , yes
a) ,no
