SOLUTION: If the perimeter of a rectangle is 260 feet and the length is 30 feet more than the width, what are the dimensions of the rectangle?

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Question 1055662: If the perimeter of a rectangle is 260 feet and the length is 30 feet more than the width, what are the dimensions of the rectangle?
Found 2 solutions by ikleyn, addingup:
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
If the perimeter of a rectangle is 260 feet and the length is 30 feet more than the width, what are the dimensions of the rectangle?
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Let W be the width, then the length is W+30.

W + (W+30) + W + (W+30) = 260,

4W + 60 = 260,

4W = 260-60  --->  4W = 200  --->  W = 200%2F4 = 50.

Answer.  The wide is 50 ft.  The length is 50+30 = 80 ft.


Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
2L+2W = Perimeter
L = W+30 substitute for L in the equation above:
2(W+30)+2W = 260
2W+60+2W = 260
4W = 200
W = 50
and
L = 50+30 = 80