SOLUTION: Sara invested equal amounts-one at 6% simple interest and the other at 5% compound interest. If the former earns $486.56 as more interest at the end of two years, find the total am

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Sara invested equal amounts-one at 6% simple interest and the other at 5% compound interest. If the former earns $486.56 as more interest at the end of two years, find the total am      Log On

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Question 1044639: Sara invested equal amounts-one at 6% simple interest and the other at 5% compound interest. If the former earns $486.56 as more interest at the end of two years, find the total amount invested
Found 3 solutions by Alan3354, josmiceli, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Sara invested equal amounts-one at 6% simple interest and the other at 5% compound interest. If the former earns $486.56 as more interest at the end of two years, find the total amount invested
--------
A = amount invested.
---
A*0.06 - A*0.05 = 486.56/2
0.01A = 243.28
A = $24328

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The formulas I like to use are:
(1) +A%5B1%5D+=+P%2A%28+1+%2B+r%5B1%5D%2At+%29+ for simple interest
(2) +A%5B2%5D+=+P%2A%28+1+%2B+r%5B2%5D%2Fn+%29%5E%28nt%29+ for compound interest
------------------------------------------------
Equal amounts were invested, so instead of +P+ in
these formulas, I will use +P%2F2+ in each one.
--------------------------------------------
There are 2 different interest rates:
+r%5B1%5D+=+.06+ for simple interest
+rt%5B2%5D+=+.05+ for compound interest
------------------------------------
+t+=+2+
+n+=+1+ because the period for compounding
must be 1 year. ( nothing else was specified )
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I'm a little confused by " $486.56 as more interest "
Is the $486.56 the actual interest earned at 6% simple interest?
Or, is that amount the difference in interest earned between
simple and compound?
I'll take a guess by removing the word "as", so $486.56
will be the difference
------------------------
Using formula (2), the interest earned is:
+%28P%2F2%29%2A%28+1+%2B+r%5B2%5D%2Fn+%29%5E%28nt%29+-+P%2F2+
--------------------------------
Using formula (1), the interest earned is:
+%28P%2F2%29%2A%28+r%5B1%5D%2At+%29+
------------------
Now I can say:


+%28P%2F2%29%2A%28+1+%2B+.12+%29+-++%28P%2F2%29%2A%28+1+%2B+.05+%29%5E%281%2A2%29+=+486.56+
+%28P%2F2%29%2A1.12+-+%28P%2F2%29%2A1.05%5E2+=+486.56+
+%28P%2F2%29%2A%28+1.12+-+1.1025+%29+=+486.56+
+P%2A.0175+=+2%2A486.56+
+P+=+973.12%2F.0175+
+P+=+55606.86+
The total amount invested was $55,606.86
-------------------
check answer:
+I%5B1%5D+=++%28P%2F2%29%2A%28+r%5B1%5D%2At+%29+
+I%5B1%5D+=+27803.43%2A.06%2A2+
+I%5B1%5D+=+3336.41+
and
+I%5B2%5D+=++%28P%2F2%29%2A%28+1+%2B+r%5B2%5D%2Fn+%29%5E%28nt%29+-+P%2F2+
+I%5B2%5D+=+27803.43%2A%28+1+%2B+.05+%29%5E2+-+27803.43+
+I%5B2%5D+=+27803.43%2A1.05%5E2+-+27803.43+
+I%5B2%5D+=+27803.43%2A1.1025+-+27803.43+
+I%5B2%5D+=+27803.43%2A.1025+
+I%5B2%5D+=+2849.85+
and
+3336.41+-+2849.85+=+486.56+
OK
You might want a 2nd opinion, too. There are probably
better ways to do it, but, hopefully, I got the
right answer.

Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!
Sara invested equal amounts-one at 6% simple interest and the other at 5% compound interest. If the former earns $486.56 as more interest at the end of two years, find the total amount invested
Let amount invested in each be P
Simple interest, @ 6%, for 2 years: P * 2 * .06, or .12P
Simple interest, @ 5%, for 2 years: P * 2 * .05, or .1P
Since the 6% earned $486.56 more than the 5%, then we get: .12P - .1P = 486.56
.02P = 486.56
P, or principal invested in EACH =