SOLUTION: michael saved 50 php in january. suppose he saved twice the amount he saved the previous month. how much would he save at the end of one year ? Use the geometric series technique
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Question 1039410: michael saved 50 php in january. suppose he saved twice the amount he saved the previous month. how much would he save at the end of one year ? Use the geometric series technique Answer by jorel555(1290) (Show Source):
You can put this solution on YOUR website! 50+100+200+400+...=50((2^n)-1)where n is the number of periods. Since n, in this case, is 12, we have:
50x((2^12)-1)=50x4095=204,800 php saved in one year!!!!!!!!!!!
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