SOLUTION: A farmer has donkeys and ostriches. There are 100 heads and 252 legs. Two donkeys have three legs each. calculate how many of each animal type the farmer has.
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Question 1026792: A farmer has donkeys and ostriches. There are 100 heads and 252 legs. Two donkeys have three legs each. calculate how many of each animal type the farmer has. Found 2 solutions by ikleyn, MathTherapy:Answer by ikleyn(52858) (Show Source):
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A farmer has donkeys and ostriches. There are 100 heads and 252 legs.
Two donkeys have three legs each. calculate how many of each animal type the farmer has.
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Distract 2*3 = 6 legs and 2 heads.
Then you will have the problem for normal animals:
A farmer has donkeys and ostriches. There are 98 heads and 246 legs.
Calculate how many of each animal type the farmer has.
For this, see the lesson Problem on animals at a farm where similar problems were solved.
Use them as samples and solve your problem by using the same logic and the same technique.
At the end do not forget to return back two heads that you distracted in the beginning.
You can put this solution on YOUR website!
A farmer has donkeys and ostriches. There are 100 heads and 252 legs. Two donkeys have three legs each. calculate how many of each animal type the farmer has.
Let the number of donkeys be D
Then number of ostriches = 100 – D
Number of donkeys with 4 legs: D – 2
We then get the following LEGS equation: 2(100 - D) + 4(D – 2) + 3(2)) = 252
200 - 2D + 4D – 8 + 6 = 252
- 2D + 4D + 198 = 252
2D = 252 – 198
2D = 54
D, or number of donkeys = , or
Number of ostriches: 100 – 27, or
