SOLUTION: Part of the proceeds from a garage sale was $460 worth of $10 and $20 bills. If there are 10 more $10 bills than $20 bills, find the number of each denomination.
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Question 1014071: Part of the proceeds from a garage sale was $460 worth of $10 and $20 bills. If there are 10 more $10 bills than $20 bills, find the number of each denomination. Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! x= y+10
10x+20y= 460
10(y+10)+20y= 460
10y+100+20y= 460
30y= 360
y= 12 You have 12 $20 bills and the problem says you have 10 more $10 bills than $20 bills:
x= 12+10= 22
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Check:
12*20= 240
22*10= 220
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Total: 460 We have the correct answer
