SOLUTION: Question 1: A Concord Jet travels 80 km/h faster than a Delta jet liner. The Concord takes one hour less than the Delta Jet to travel a journey of 6280 km.
Denoting the speed
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-> SOLUTION: Question 1: A Concord Jet travels 80 km/h faster than a Delta jet liner. The Concord takes one hour less than the Delta Jet to travel a journey of 6280 km.
Denoting the speed
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Question 987367: Question 1: A Concord Jet travels 80 km/h faster than a Delta jet liner. The Concord takes one hour less than the Delta Jet to travel a journey of 6280 km.
Denoting the speed of the Delta Jet Liner by x km/h:
(a) Write down in terms of x expressions for the time taken by:
(i) The Delta Jet Liner
(ii) The Concord Liner
(b) Form an equation to connect these times and show that it simplifies to x2 + 80x - 502400 = 0
(c) Hence find the speed of both aircrafts to the nearest km/h
Question 2: The ratio of the prices of two different sheets of glass is 2:5. The total bill for 20 sheets of the cheaper glass and 10 sheets of the more expensive one is $1080. If d dollars represent the cost of one sheet of the cheaper glass, determine
(i) An expression in d for the cost of ONE sheet of the more expensive glass
(ii) The value of d
(iii) The cost of ONE sheet of the more expensive glass
Question 3: Two rectangular plots are equal in area. The length of the first plot is one and a half times its width. The length of the second plot is 7 m less than three times its width.
(a) Denoting the width of the first plot by x m and the width of the second plot by y m, derive a relation between x and y.
(b) If y = x + 1, calculate the values of x and y.
Many thanks...these 3 problems really baffle me.
Exactly what part of "One problem per post" is too difficult for you to comprehend?
3(a). represents the width of the first rectangle, so the length of the first rectangle is and therefore the area of the first rectangle is . represents the width of the second rectangle, so the length of the second rectangle is and the area of the second rectangle is then . Since the two areas are equal:
John
My calculator said it, I believe it, that settles it
