SOLUTION: The cost of operating an appliance varies jointly the number of watts drawn, the hours of operation and the cost per kilowatt-hour. At 1.75 per kilowatt-hour, how much would it cos

Algebra ->  Customizable Word Problem Solvers  -> Evaluation -> SOLUTION: The cost of operating an appliance varies jointly the number of watts drawn, the hours of operation and the cost per kilowatt-hour. At 1.75 per kilowatt-hour, how much would it cos      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 987133: The cost of operating an appliance varies jointly the number of watts drawn, the hours of operation and the cost per kilowatt-hour. At 1.75 per kilowatt-hour, how much would it cost when a 500-watt waffle iron operates for 45 minutes?
Found 2 solutions by CubeyThePenguin, ikleyn:
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
cost = ($1.75/kWh) * (0.5 kW) * (0.75 h) = $0.66 (rounded to the nearest cent)

Answer by ikleyn(52777) About Me  (Show Source):
You can put this solution on YOUR website!
.

For realistic current prices for kwh in the US see this source

https://www.electricchoice.com/electricity-prices-by-state/

The prices vary from state to state, but they are in the range from 12 to 20 cents per kwh.