SOLUTION: Hi, I'm unsure about this equation, could you tell me if it is right or wrong? And if it is wrong, could you please tell me how to get the right answer? Thank you so much!! Proble

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Question 9297: Hi, I'm unsure about this equation, could you tell me if it is right or wrong? And if it is wrong, could you please tell me how to get the right answer? Thank you so much!!
Problem: A rectangle and a square have the same width but the rectangle is 5 m longer than the square. Their total area is 133m2. Find the dimensions of each figure. Choices for the square's width: 6, 7, 8.
This is what I have and need to know if it is right or wrong:
This is my equation: W times W times W times W + w(w+7) = 133m2
I found that 7 substituted for w works, so I got these diminsions: Square: 7 by 7
and Rectangle: 12 by 7
Is this right?? Please help quickly!! Thank you so much!!
P.S. I don't know how to get the times sign or any or those other signs on my computer, so I hope that was good enough! Thanks!!

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
i think your equation is written incorrectly, but you have the correct answer.

Let width of square = w
so, rectangle length = w+5

Area of square = w%5E2
Area of rectangle = w(w+5) --> w%5E2+%2B+5w

together these areas equal 133, so w%5E2+%2B+5w+%2B+w%5E2+=+133

2w%5E2+%2B+5w+=+133
2w%5E2+%2B+5w+-+133+=+0
(2w+19)(w-7) = 0

so ignoring the first bracket, as this gives a negative answer, we have w=7.

so square is 7x7
and rectangle is 7x12.

jon.