SOLUTION: Rectangular lot: The length of a rectangular lot is 50 feet more than the width. If the perimeter is 500 feet, then what are the length and width?

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Question 78690: Rectangular lot:
The length of a rectangular lot is 50 feet more than the width. If the perimeter is 500 feet, then what are the length and width?

Answer by tutor_paul(519) About Me  (Show Source):
You can put this solution on YOUR website!
This problem boils down to developing 2 equations with 2 unknowns. From the
information given, the first step is to figure out how to write the equations.
First, you are given that the length is 50 feet more than the width. You can write that as:
l=w%2B50
Then, you are given the perimeter of the rectangle to be 500 feet. You can write that as:
2l%2B2w=500 (Recall that perimeter is the length of all sides)
So now you have two equations with 2 unknowns. That means you can solve for l and w.
You already have an equation for l, so just plug that in to the second equation:
2%28w%2B50%29%2B2w=500
2w%2B100%2B2w=500
4w=400
w=100
Now that you have w, plug that into the first equation and you can get the length. I'll leave that part to you.
Good Luck,
tutor_paul@yahoo.com