Question 68041: The sum of three consecutive odd integers is 201. Find the integers. Found 2 solutions by josmiceli, JohnsenP:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let the one integer be x,
The second integer be x+2,
The third integer is then x+4,
If their sum is 201, the equation is
x + ( x + 2 ) + ( x + 4 ) = 201
3x + 6 - 6 = 201 - 6
3x = 195
3x/3 = 195/3
x = 65 first odd integer
Plug 65 to the second integer yields, 65 + 2 = 67
Plug 65 to the third integer yields, 65 + 3 = 69
Proof;
65 + 67 + 69 = 201
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