Question 570943: What quantity of a 55% acid solution must be mixed with a 25% solution to produce 400 mL of a 40% solution? Found 2 solutions by Alan3354, Maths68:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! What quantity of a 55% acid solution must be mixed with a 25% solution to produce 400 mL of a 40% solution?
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40% is the average of 55% and 25%, so it's equal amounts.
You can put this solution on YOUR website! Solution A
Amount = x
Concentration = 55%=0.55
Solution B
Amount = 400-x
Concentration = 25%=0.25
Resultant Solution
Amount = 400
Concentration = 40% =0.4
(Amount of A)(concentration of A)+ (Amount of B)(concentration of B)= (Amount of resultant)(concentration of resultant)
(x)(0.55)+(400-x)(0.25)=(400)(0.4)
0.55x+100-0.25x=160
0.55x-0.25x=160-100
0.3x=60
0.3x/0.3=60/0.3
x=200
200ml of a 55% acid solution must be mixed with a 200ml of 25% solution to produce 400 mL of a 40% solution
