SOLUTION: if (3y-1)(2y+k)=ay^2+by=5 for all values of y, what is the value of a+b?
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Question 472146
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if (3y-1)(2y+k)=ay^2+by=5 for all values of y, what is the value of a+b?
Answer by
jorel1380(3719)
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(3y-1)(2y+k)=ay^2+by=5
ay2+by-5=0
(3y-1)(2y+5)=0
6y2+13y-5=0
a+b=6+13=19..