SOLUTION: A certain .22 caliber gun fires a bullet at a speed of 1192 feet per second. If the .22 caliber gun is fired straight upward into the sky, the height of the bullet in feet is given

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Question 400646: A certain .22 caliber gun fires a bullet at a speed of 1192 feet per second. If the .22 caliber gun is fired straight upward into the sky, the height of the bullet in feet is given by the equation , h=-16t^2 +1192t where t is the time in seconds with t=0 corresponding to the instant the gun is fired. How long is the bullet in the air?

Answer by ankor@dixie-net.com(22740) (Show Source):
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A certain .22 caliber gun fires a bullet at a speed of 1192 feet per second.
If the .22 caliber gun is fired straight upward into the sky, the height of
the bullet in feet is given by the equation , h=-16t^2 +1192t where t is the
time in seconds with t=0 corresponding to the instant the gun is fired.
How long is the bullet in the air?
:
The bullet will be at h=0 twice, when it is shot and when it returns so we have:
-16t^2 + 1192t = 0
factor out -t, results:
-t(16t - 1192) = 0
t = 0
and
16t = 1192
t =
t = 74.5 seconds