SOLUTION: MX Labs needs to make 500 gallons of 34% acid solution. The only solutions available are a 25% acid solution and a 50% acid solution. How many gallons of each solution should be mi
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Question 391607: MX Labs needs to make 500 gallons of 34% acid solution. The only solutions available are a 25% acid solution and a 50% acid solution. How many gallons of each solution should be mixed to make the 34% solution? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! let x=gallons of 25% solution
500-x = gallons of 50% solution
the total amount of acid in the two solutions = total acid in the final solution
.25x+.5(500-x) =.34(500)
.25x+250-.5x =170
.25x = 80
x=80/.25 = 320
500-x = 500-320 = 180
ans: 320 gal of 25% solution and 180 gal of 50% solution are required to make 500 gal of 34% solution
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