SOLUTION: Water is leaking from a tank at a constant rate of 20% per hour. If yn denotes the amount of water at the beginning of the hour, in how many hours would Yn ≤ y1/10?

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Question 374254: Water is leaking from a tank at a constant rate of 20% per hour. If yn denotes the amount of water at the beginning of the hour, in how many hours would Yn ≤ y1/10?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I take this to mean the water left in the tank
is less than or equal to 1/10 of the starting
amount of water after n hours
after 1st hour: y%5B1%5D+-+.2y%5B1%5D+=+.8y%5B1%5D
after 2nd hour: .8y%5B1%5D+-+.2%2A.8y%5B1%5D+=+.8%5E2%2Ay%5B1%5D
after 3rd hour: .8%5E2%2Ay%5B1%5D+-+.2%2A.8%5E2%5B1%5D+=+.8%5E3%2Ay%5B1%5D
The pattern here is that after n hours,
the amount of water left in the tank is
.8%5En%2Ay%5B1%5D
The problem wants to know when .8%5En%2Ay%5B1%5D+%3C=+%281%2F10%29%2Ay%5B1%5D
The y%5B1%5D's cancel from both sides leaving:
.8%5En+%3C=+1%2F10
10%2A%28.8%5En%29+%3C=+1
Note that .8%5En+=+8%5En%2A10%5E%28-n%29
10%2A10%5E%28-n%29%2A+8%5En+%3C=+1
10%5E%28-n+%2B+1%29%2A8%5En+%3C=+1
Take the log base 10 of both sides
1+-+n+%2B+n%2Alog%288%29+%3C=+0
n%2A%28log%288%29+-+1%29+%3C=+-1
Now I need to multiply both sides by
-1 which reverses the < sign
n+%3E=+1%2F%281+-+log%288%29%29
n+%3E=+1%2F%281+-+.90309%29
n+%3E=+1%2F.09691
n+%3E=+10.3189
Or, n+%3E=+10 in whole numbers
The answer is
y%5B10%5D+%3C=+%281%2F10%29%2Ay%5B1%5D
Unless I messed up- I think the approach is right