SOLUTION: can you solve this pauls flag has a perimeter of 28 feet. find the dimensions of the flag if the length is 4 feet less than twice its width

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Question 373455: can you solve this
pauls flag has a perimeter of 28 feet. find the dimensions of the flag if the length is 4 feet less than twice its width
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let L = length
Let W = width
the formula for perimeter is
2L+%2B+2W
given:
2L+%2B+2W+=+28
L+=+2W+-+4
---------------
By substitution:
2%2A%282W+-+4%29+%2B+2w+=+28
4W+-+8+%2B+2W+=+28
6W+=+28+%2B+8
6W+=+36
W+=+6
and, since
L+=+2W+-+4
L+=+2%2A6+-+4
L+=+8
The length is 8 ft and the width is 6 ft