SOLUTION: the AVERAGE weight of the top 5 fish caught in the tournament was 12.3 lbs. The second fish weighed 12.8 lbs. the third fish weighed 12.6 lbs, the fourth fish weighed 11.8lbs and t

Algebra ->  Customizable Word Problem Solvers  -> Evaluation -> SOLUTION: the AVERAGE weight of the top 5 fish caught in the tournament was 12.3 lbs. The second fish weighed 12.8 lbs. the third fish weighed 12.6 lbs, the fourth fish weighed 11.8lbs and t      Log On

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Question 358917: the AVERAGE weight of the top 5 fish caught in the tournament was 12.3 lbs. The second fish weighed 12.8 lbs. the third fish weighed 12.6 lbs, the fourth fish weighed 11.8lbs and the 5th fish weighed 9.7 lbs. What was the weight of the heaviest fish?
PLEASE EXPLAIN THE STEPS INVOLVED. My teacher does not explain how to arrive at the answer or how to figure out a an average with one of the numbers missing.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
the AVERAGE weight of the top 5 fish caught in the tournament was 12.3 lbs. The second fish weighed 12.8 lbs. the third fish weighed 12.6 lbs, the fourth fish weighed 11.8lbs and the 5th fish weighed 9.7 lbs. What was the weight of the heaviest fish?
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Total weight of the 5 fish is 5*12.3 = 61.5 lbs.
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wt of 1st fish = x
wt of 2nd fish = 12.8 lbs
wt of 3rd fish = 12.6 lbs
wt of 4th fish = 11.8 lbs
wt of 5th fish = 9.7 lbs
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Solve: x + sum of 4 fish = 61.5 lbs
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x + 46.9 = 61.5
x = 14.6 lbs.
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The heaviest fish was 14.6 lbs.
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Cheers,
Stan H.