SOLUTION: Need to solve the following problem in 2 different ways:
The Math Club sold roses and tulips this year for Valentine's Day. The number of roses sold was 8 more than 4 times the n
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The Math Club sold roses and tulips this year for Valentine's Day. The number of roses sold was 8 more than 4 times the n
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Question 247605: Need to solve the following problem in 2 different ways:
The Math Club sold roses and tulips this year for Valentine's Day. The number of roses sold was 8 more than 4 times the number of tulips sold. tulips were sold for $2 each and roses for $5 each. The club made $414.00. How many roses were sold? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Need to solve the following problem in 2 different ways:
The Math Club sold roses and tulips this year for Valentine's Day.
The number of roses sold was 8 more than 4 times the number of tulips sold.
r = 4t + 8
:
tulips were sold for $2 each and roses for $5 each. The club made $414.00.
2t + 5r = 414
:
How many roses were sold?
Replace r in the above equation with (4t+8). find t
2t + 5(4t+8) = 414
2t + 20t + 40 = 414
22t = 414 - 40
22t = 374
t =
t = 17 tulips sold
:
Find the no. of roses using; r = 4t + 8
r = 4(17) + 8
r = 68 + 8
r = 76 roses
;
:
Another way
r = 4t + 8
or
4t = r - 8
Divide by 4
t = .25r - 2
:
2t + 5r = 414
Substitute for t
2(.25r - 2) + 5r = 414
.5r - 4 + 5r = 414
5.5r = 414 + 4
5.5r = 418
r =
r = 76 roses again
